Crystal Lake named the cheapest suburb in the USA
CHICAGO, IL — The Chicago suburbs dominate a list of the 100 most affordable suburbs live in the country with Premier.
In fact, eight suburbs make the top ten on the list, with Crystal Lake taking first place. Researchers at StorageCafe analyzed Zillow data on home prices in the top 100 suburbs, along with other factors, to determine where homebuyers can pay less for convenience-rich living.
The average cost of a home in a prime suburb is $848,880, more than double the national average of $331,530.
However, according to the study, homes in Crystal Lake cost an average of $301,750, significantly less than the national average and less than the Chicago metro average of $309,268.
The other budget Chicago suburbs topping the list are Algonquin and Elk Grove Village in second and third place. Researchers said both communities have good schools, are friendly, and have good access to outdoor recreation opportunities like Crystal Lake.
Bloomingdale ranks fifth, Vernon Hills sixth, Buffalo Grove seventh, Orland Park eighth, and Morton Grove ninth.
It’s also worth noting that Lake Zurich, Downers Grove and Frankfurt landed eleventh, twelfth and thirteenth on the list, respectively, and Geneva was 16th.
On the other hand, the top ten suburbs with the highest home prices are all in California.
The full list of the top ten suburbs including average home prices according to StorageCafe is below.
- 1. Crystal Lake, IL – $301.7572
- 2. Algonkin, IL – $331,258
- 3. Elk Grove, IL – $331,338
- 4. Snellville, GA – $335,538
- 5. Bloomingdale, Illinois – $344,964
- 6. Vernon Hills, Illinois – $351,844
- 7. Buffalo Grove, Illinois – $366,486
- 8th. Orlando Park, Illinois – $368,057
- 9. Morton Grove, Illinois – $374,168
- 10 North Haven, Connecticut – $375,380
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https://wgntv.com/news/wgn-news-now/chicago-suburbs-tops-for-most-affordable-with-premier-living/ The Chicago suburbs are the cheapest with prime living